VBA – Get Today’s Date (Current Date)

This tutorial demonstrates how to get today’s date in VBA.

There are a couple of ways to obtain today’s date in VBA code, namely using the VBA Date() Function or the VBA Now() Function.

Date() Function

The Date() Function returns today’s date. In the example below, we assign today’s date to a variable and then display the date in the immediate window in the VBE Editor.

Dim dtToday as Date
dtToday = Date()
Debug.Print dtToday

Alternatively, we can display the date in a message box.

Sub TestDate
  Dim dtToday as Date
  dtToday = Date()
  Msgbox "Today's date is " & dtToday
End Sub

Now() Function

The Now() Function works in the same way as the Date Function, but it also includes the time.

Sub TestDate()
  Dim dtToday As Date
  dtToday = Now()
  MsgBox "Today's date is " & dtToday
  End Sub

Formatting Dates With VBA

In both the Date() and the Now() Functions, the date is formatted in a default style as determined by the PC settings. We can customize this formatting using the VBA Format Function. The Format Function returns a string, so we need to declare a STRING variable rather than a DATE variable.

Sub TestDate()
  Dim dtToday As String
  dtToday = Format (Date, "dd mmmm yyyy")
  MsgBox "Today's date is " & dtToday
End Sub

We can also format the Now() Function to include the time portion in a customized format.

Sub FormatNow()
  Dim dtToday As String
  dtToday = Format(Now(), "dd mmmm yy hh:mm:ss am/pm")
  MsgBox dtToday
End Sub

Comparing Two Dates with VBA

We can also use the Date Function to compare today’s date with a different date. For example, we might want to calculate how many days there are until an event! We can do this using the VBA DateDiff() Function which will return a number. We can therefore declare an INTEGER variable to store the returned value in.

Sub TestDateDiff()
  Dim dtToday As Date
  Dim dtSomeDay As Date
  Dim iDays As Integer
  dtToday = Date
  dtSomeDay = "05/06/2021"
  iDays = DateDiff("d", dtToday, dtSomeDay)
  MsgBox "There are " & iDays & " days between the two dates"
End Sub

As dates are stored as numbers, we could also subtract the second date from the first to obtain the same answer.

iDays = dtToday - dtSomeDay

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